(X-3+16)x-3=x+3^

Solution for (X-3+16)x-3=x+3^ equation:

(X-3+16)X-3=X+3^

We move all terms to the left:

(X-3+16)X-3-(X+3^)=0

We add all the numbers together, and all the variables

(X+13)X-(X+3^)-3=0

We multiply parentheses

X^2+13X-(X+3^)-3=0

We get rid of parentheses

X^2+13X-X-3-3^=0

We add all the numbers together, and all the variables

X^2+12X=0

a = 1; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·1·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*1}=\frac{-24}{2}
=-12
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*1}=\frac{0}{2}
=0
$